MLton 20070826 Printf
Home  Index  
Programmers coming from C or Java often ask if Standard ML has a printf function. It does not. However, it is possible to implement your own version with only a few lines of code.

Here is a definition for printf and fprintf, along with format specifiers for booleans, integers, and reals.

structure Printf =
   struct
      fun $ (_, f) = f (fn p => p ()) ignore
      fun fprintf out f = f (out, id)
      val printf = fn z => fprintf TextIO.stdOut z
      fun one ((out, f), make) g =
         g (out, fn r =>
            f (fn p =>
               make (fn s => 
                     r (fn () => (p (); TextIO.output (out, s))))))
      fun ` x s = one (x, fn f => f s)
      fun spec to x = one (x, fn f => f o to)
      val B = fn z => spec Bool.toString z
      val I = fn z => spec Int.toString z
      val R = fn z => spec Real.toString z
   end

Here's an example use.

val () = printf `"Int="I`"  Bool="B`"  Real="R`"\n" $ 1 false 2.0

This prints the following.

Int=1  Bool=false  Real=2.0

In general, a use of printf looks like

printf <spec1> ... <specn> $ <arg1> ... <argm>

where each <speci> is either a specifier like B, I, or R, or is an inline string, like `"foo". A backtick (`) must precede each inline string. Each <argi> must be of the appropriate type for the corresponding specifier.

SML printf is more powerful than its C counterpart in a number of ways. In particular, the function produced by printf is a perfectly ordinary SML function, and can be passed around, used multiple times, etc. For example:

val f: int -> bool -> unit = printf `"Int="I`"  Bool="B`"\n" $
val () = f 1 true
val () = f 2 false

The definition of printf is even careful to not print anything until it is fully applied. So, examples like the following will work as expected.

val f: int -> bool -> unit = printf `"Int="I`"  Bool="B`"\n" $ 13
val () = f true
val () = f false

It is also easy to define new format specifiers. For example, suppose we wanted format specifiers for characters and strings.

val C = fn z => spec Char.toString z
val S = fn z => spec (fn s => s) z

One can define format specifiers for more complex types, e.g. pairs of integers.

val I2 = 
   fn z => 
   spec (fn (i, j) => 
         concat ["(", Int.toString i, ", ", Int.toString j, ")"])
   z

Here's an example use.

val () = printf `"Test "I2`"  a string "S`"\n" $ (1, 2) "hello"

Printf via fold

Printf is best viewed as a special case of variable-argument Fold that inductively builds a function as it processes its arguments. Here is the definition of a Printf structure in terms of fold. The structure is equivalent to the above one, except that it uses the standard $ instead of a specialized one.

structure Printf =
   struct
      fun fprintf out =
         Fold.fold ((out, id), fn (_, f) => f (fn p => p ()) ignore)

      val printf = fn z => fprintf TextIO.stdOut z

      fun one ((out, f), make) =
         (out, fn r =>
          f (fn p =>
             make (fn s =>
                   r (fn () => (p (); TextIO.output (out, s))))))
         
      val ` =
         fn z => Fold.step1 (fn (s, x) => one (x, fn f => f s)) z

      fun spec to = Fold.step0 (fn x => one (x, fn f => f o to))

      val B = fn z => spec Bool.toString z
      val I = fn z => spec Int.toString z
      val R = fn z => spec Real.toString z
   end

Viewing printf as a fold opens up a number of possibilities. For example, one can name parts of format strings using the fold idiom for naming sequences of steps.

val IB = fn u => Fold.fold u `"Int="I`" Bool="B
val () = printf IB`"  "IB`"\n" $ 1 true 3 false

One can even parametrize over partial format strings.

fun XB X = fn u => Fold.fold u `"X="X`" Bool="B
val () = printf (XB I)`"  "(XB R)`"\n" $ 1 true 2.0 false

Also see


Last edited on 2007-08-15 22:07:07 by MatthewFluet.